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^{2 }= 1/a^{2 }+ 1/b^{2}.^{2}/2bc) (b^{2}/2ca) (c^{2}/2ab)=?_{1}x and y=m_{2}_{}x for two of its sides,where m_{1}and m_{2}are the roots of the equation x^{2}+ax-1=0,then find the orthocentre of triangle[answer:4rt2]

2x-3y+5=0(a) In slope - intercept form and hence find slope & Y-intercept

(b) In intercept form and hence find intercept on axes.

(c) In normal form and hence find perpendicular distance from the origin and angle made by the perpendicular with the positive x-axis.

^{2}-2xy-y^{2}=0 with x-axis is?(1) exactly one value of λ. (2) exactly two values of λ. (3) exactly three values of λ. (4) infinitely many values of λ.

^{2}-xy+4cy^{2}=0 is 3x+4y=0,then c=?^{2}-4xy+y^{2}=0 is?

Find the equation of angle bisectors of the pair of lines given by:

x

^{2}+4xy+y^{2}=0.How to determine the slope from the given equation .? is it co-efficient of y/co-efficient of x...or minus of co-efficient of y/co-efficient of x..??? plzz. answer fast^{2}+b^{2}+c2 = 3abc , then the line ax + by +c = 0 passes through ?(A) 3 (B) 6 (C)8 (D) 12

l=>_{1}5x-y+4=0, l, l_{2}=> 3x-y+5=0_{3}=> x+y+8=0 as the sides of a triangle. Find tangents of interior angle. Also find the nature of the triangle.x+5y+10=0; 5x+y+10=0; x-5y-10=0; 5x-y-10=0