Two schools decided to award prizes to their teachers for two qualities knowledge and guidance. School A decided to award a total of Rs. 3200 for the values to 4 and 3 teachers respectively while school B decided to award a total of Rs. 1600 for the values to 1 and 2 teachers respectively. Represent the above situation by a system of linear equations and solve using matrices. Which quality you prefer to be rewarded most and why?

Let x be knowledge and y be guidance then the equation formed are
For School A
4x+3y=3200.................(1)
For School B
x+2y=1600...................(2)
Using matrices

4312xy=32001600So, xy=4312-132001600Now,to calculate4312-1First we calculate D=4312=4×2-1×3=8-3=5So, inverse 4312-1 =152-3-14now,xy=152-3-1432001600xy=156400-4800-3200+6400=1516003200=320640x=320, y=640
Since y>x
Hence Guidance is more preferrred than knowledge

  • -1
4x + 3y = 3200,x + 2y = 1600

x = 400, y = 600 0.

0.

000

4x+3y=3200

x+2y=1600

x=320,y=640

  • 0

4X+3Y=3200

X+2Y=1600

X=320,Y=640

  • 0
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