Two particles A and B are in motion. If the wavelength associated with particle A is 5x10^-8m, calculate wavelength associated with B if its momentum is half of A

Momentum = h/wavelenth

p = h/lambda

Wavelength of the particle A = 5 x 10

^{-8}m

Let the momentum of particle A is p

_{A }and the momentum of the particle B is pB

Relation between p

_{A}and p

_{B}is :

p

_{B}= p

_{A}/2

p

_{A}= h/ 5 x 10

^{-8}m

p

_{B}= h/ 5 x 10

^{-8}m x 2

Wavelength of B(lambda) = h/p

_{B}

= h/ h/ 5 x 10

^{-8}m x 2

= 10 x 10

^{-8}m

= 10

^{-7}m

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