the tangent to curv y= x^2 + 6 at a point 1,7 touches the circle x^2+y^2+16x+12y+c=0 at a point q then the coordinates of q are :
ans = -6,-7
The tangent to the curve at point (1,7) is given by:
if equation (1) is the tangent to the circle
substituting the value of y from eq(2),
since the line (1) touches the given circle, then discriminant of eq(3) must be zero:
thus equation (3) can be rewritten as
for
if the point of contact is Q, then the coordinates of Q are
hope this helps you
if equation (1) is the tangent to the circle
substituting the value of y from eq(2),
since the line (1) touches the given circle, then discriminant of eq(3) must be zero:
thus equation (3) can be rewritten as
for
if the point of contact is Q, then the coordinates of Q are
hope this helps you