The sum of three consecutive multiples of 7 is 84. Find the three multiples. Share with your friends Share 3 Varun.Rawat answered this Let the 3 consecutive multiples of 7 be 7x, 7x + 7 and 7x + 14.Now, according to question : 7x + 7x + 7 + 7x + 14 = 84⇒21x + 21 = 84⇒21x = 84 - 21⇒21x = 63⇒x = 6321 = 3So, consecutive multiples are :7x = 7×3 = 217x + 7 = 21 + 7 = 287x + 14 = 21 + 14 = 35Hence, required multiples are : 21, 28 and 35. 3 View Full Answer Omkar Kulkarni answered this 21,28,35 is the answer 0
