The root of the quadratic equation x^2+5x-(alpha+1)(alpha+6)=0 where alpha is the constant are, 1. alpha+1, alpha+6 2. alpha+1, -(alpha+6) 3. -(alpha+1), alpha+6 4. -(alpha+1), -(alpha+6) Share with your friends Share 8 Varun.Rawat answered this The given quadratic equation is, x2 + 5x - α+1α+6 = 0⇒x2 + α+6x - α+1x - α+1α+6 = 0⇒xx + α+6 - α+1x + α+6 = 0⇒x - α+1x + α+6 = 0⇒x - α+1 = 0 or x + α+6 = 0⇒x = α+1 or x = - α+6 4 View Full Answer Hpr answered this Option 2 is correct 0
