the rate of diffusion of methane is twice that of gas x , when diffuse through same hole under all identical conditions. the molecular mass ofgasx is
1)64
2) 80 3) 332
Dear User,
Let rate of diffusion of gas x, r1 = a
Therefore, rate of diffusion of methane,r2 = 2 a
According to Graham's Law of Diffusion
Hence, the correct answer is 1) 64 g
Let rate of diffusion of gas x, r1 = a
Therefore, rate of diffusion of methane,r2 = 2 a
According to Graham's Law of Diffusion
Hence, the correct answer is 1) 64 g