the rate of diffusion of methane is twice that of gas x , when diffuse through same hole under all identical conditions. the molecular mass ofgasx is
2) 80 3) 332

Dear User,
Let rate of diffusion of gas x, r1 = a
Therefore, rate of diffusion of methane,r2 = 2 a
According to Graham's Law of Diffusion
r1r2=M2M1M1 = Molecular mass of gas x M2 = Molecular mass of Methane = 16 gTherefore,a2a= 16M2Squaring both the sides,14=16M2or, M2 = 16×4=64 g
Hence, the correct answer is 1) 64 g

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