The ionization constant of a base (C2H5)3N is 6.4*10^-5. calculate its degree of dissociation in its 0.1 M solution when mixed with 0.01M NaOH solution.

Dear student

  • 141
6.4 X 10*3
  • -71
Degree of dissociation = Ka / Concentration of strong electrolyte having common ion added = (6,4 × 10^-5) / 0.01 = 6.4 × 10^-3
  • 35
I don't know
  • -40
This is the solution:

  • 2
What are you looking for?