The ionization constant of a base (C2H5)3N is 6.4*10^-5. calculate its degree of dissociation in its 0.1 M solution when mixed with 0.01M NaOH solution. Share with your friends Share 35 Nikhil Kalra answered this Dear student 141 View Full Answer Hitesh answered this 6.4 X 10*3 -71 Shahin answered this Degree of dissociation = Ka / Concentration of strong electrolyte having common ion added = (6,4 × 10^-5) / 0.01 = 6.4 × 10^-3 35 Dilruba Khan answered this I don't know -40 Jk answered this This is the solution: 2