The coordinates of the three corners of a shaded face on a cubic unit cell are 12,12,1, 0, 1, 12 - Chemistry - The Solid State

Question

The coordinates of the three corners of a shaded face on a cubic
unit cell are 1 2 , 1 2 , 1 ,   0 ,   1 ,   1 2
  and   1 ,   1 ,   1 2 as shown below in the
figure Determine the Miller indices of the plane

Bharti Paliwal · Accepted Answer

Dear StudentSteps to find miller indices:1
 Reciprocate the intercept given2
 Clear the fractions In the query above,Miller indices for (12,12,1) = 2,2,1Miller indices for (0,1,12) = 10,1,2=0,1,2  {10=∞, but to avoid the infinity situation of miller indices we take it as 0}Miller indices for (1,1,12) = 1,1,2Regards

The coordinates of the three corners of a shaded face on a cubic unit cell are 1 2 , 1 2 , 1 , 0 , 1 , 1 2 and 1 , 1 , 1 2 as shown below in the figure. Determine the Miller indices of the plane.

The coordinates of the three corners of a shaded face on a cubic unit cell are $(\frac{1}{2}, \frac{1}{2}, 1), (0, 1, \frac{1}{2}) and (1, 1, \frac{1}{2})$ as shown below in the figure. Determine the Miller indices of the plane.