t1/2 of a zero order reaction is 10 minutes. what time reactant will one fourth of initial value

Dear Student,

Half life of zeroth order reaction = t_1/2 = 10 min
$t_{1/2 }= \frac{[A{]}_o}{2k}$
$k= \frac{[A{]}_o}{2t_{1/2 }}$
Suppose [A]o = 1 M
After time t, [A] = 0.25 M
$k= \frac{1}{2\times 10}$ = 0.05 M min^-1
To calculate time t,
^{$t = \frac{[A{]}_o-[A]}{k}$}
$t = \frac{1-0.25}{0.05}$ = 15 min
time taken to become one fourth is 15 min


Regards