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Please find below the solution to the asked query:

Given : Mr. Durani bought a land for Rs 180000 and the value of land grows uniformly by 30 % per annum .

We know formula for compound interest : Amount =

*P*${\left(1+\frac{r}{100}\right)}^{t}$ , So

Cost of land after three years = 180000${\left(1+\frac{30}{100}\right)}^{3}=180000{\left(1+\frac{3}{10}\right)}^{3}=180000{\left(\frac{13}{10}\right)}^{3}=180000{\left(1.3\right)}^{3}=180000\times 2.197$ =

**395460**

And

Mr. Durani also bought a car for Rs 320000 and the value of car depreciates 20 % for first year and 15 % thereafter

We know formula for compound interest when we have succesive rate that are depreciates : Amount =

*P*$\left\{\left(1-\frac{{r}_{1}}{100}\right)\left(1-\frac{{r}_{2}}{100}\right)...\right\}$ , So

Cost of car after three years = 320000$\left(1-\frac{20}{100}\right)\left(1-\frac{15}{100}\right)\left(1-\frac{15}{100}\right)=320000\left(1-\frac{1}{5}\right)\left(1-\frac{3}{20}\right)\left(1-\frac{3}{20}\right)=320000\times \frac{4}{5}\times \frac{17}{20}\times \frac{17}{20}=160\times 4\times 17\times 17$ =

**184960**

Then,

Mr . Durani gets total profit of loss in all transiction = 395460 + 184960 - 180000 - 320000 = 80420 ( That is positive so Mr . Durani gets profit )

Therefore,

**Total profit Mr. Durani gets = Rs . 80420 ( Ans )**

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