Solve this:-
Solve this:- ​ In AABC, Z B = 900. L & M trisect BC. Fig. 11. Prove that = 5AL2 + 3AC2. c Fig. 11 8. 9. In A ABC , D is the midpoint of BC and AE BC. 1 Prove that: AB2+ = 2 AD2+ —BC2 OR AB2+ AC2= 2AD2 +2BD2 BC2 In AABC ZACB = 900 and CD AB. Prove that AC2 AD

Dear Student,


solving 7letMC=ML=LB=xAB2+x2=AL2AB2+4x2=AM2AB2+9x2=AC2eliminate x and AB3x2=AM2-AL2AL2+8x2=AC28AM2=5AL2+3AC2Regards

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