Solve this:
Q. If solubility of any gas in the liquid at 1 bar pressure is 0.05 mol/L. What will be its solubility at 3 bar pressure, keeping the temperature constant ? ..
Dear student ,
Acc. to Henry's law ; S / P = KH
since in both the conditions gas is same then KH will also the same value
( 1) (2)
S /P = S / P
0.05 / 1 = S / 3
S = .15 mol/ L (option 2)
Regards
Acc. to Henry's law ; S / P = KH
since in both the conditions gas is same then KH will also the same value
( 1) (2)
S /P = S / P
0.05 / 1 = S / 3
S = .15 mol/ L (option 2)
Regards