Dear Student, In a right-angled triangle hypotenuse2 = base2+perpendicular2,hypotenuse = 72+72= 49+49= 98= 72 cmPerimeter of isosceles triangle = Sum of all sides= 7+7+72 = 14+72 = 72+2 cm Regards

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Solve it please Find the perimeter of an isosceles right angled triangle with each of its congruent sides as 7 cm.

Dear Student,

I n a r i g h t - a n g l e d t r i a n g l e h y p o t e n u s e^{2} = b a s e^{2} + p e r p e n d i c u l a r^{2}, h y p o t e n u s e = \sqrt{7^{2} + 7^{2}} = \sqrt{49 + 49} = \sqrt{98} = 7 \sqrt{2} c m P e r i m e t e r o f i s o s c e l e s t r i a n g l e = S u m o f a l l s i d e s = 7 + 7 + 7 \sqrt{2} = 14 + 7 \sqrt{2} = 7 (2 + \sqrt{2}) c m

Regards

-2

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Solve it please Solve it please Find the perimeter of an isosceles right angled triangle with each of its congruent sides as 7 cm.

Solve it please

Solve it please Find the perimeter of an isosceles right angled triangle with each of its congruent sides as 7 cm.