show that the function f(x)= sin (2x+ pie/4) is decreasing in 3pie/8 <x<5 pie/8

Dear student
We have,f(x)=sin2x+π4f'(x)=2cos2x+π4Here,3π8<x<π5π83π4<2x<π5π4π<2x+π4<3π2cos2x+π4<0    cos function is negative in third quadrant2cos2x+π4<0f'(x)<0 ,x3π8,5π8So, f(x) is decreasing on 3π8,5π8.
Regards

  • 1
let y=f(x)  dy/dx =2cos(2x +pi/4) now equate it to 0.   cos(2x+pi/4)=0 ==>  2x+pi/4=pi/2   =  2x=pi/4 => x=pi/8
now plot it on number line and check for its monotonicity 
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