show that the function f(x)= sin (2x+ pie/4) is decreasing in 3pie/8 <x<5 pie/8 Share with your friends Share 0 Neha Sethi answered this Dear student We have,f(x)=sin2x+π4f'(x)=2cos2x+π4Here,3π8<x<π5π8⇒3π4<2x<π5π4⇒π<2x+π4<3π2⇒cos2x+π4<0 ∵cos function is negative in third quadrant⇒2cos2x+π4<0⇒f'(x)<0 ,∀x∈3π8,5π8So, f(x) is decreasing on 3π8,5π8. Regards 1 View Full Answer Adithya answered this let y=f(x) dy/dx =2cos(2x +pi/4) now equate it to 0. cos(2x+pi/4)=0 ==> 2x+pi/4=pi/2 = 2x=pi/4 => x=pi/8 now plot it on number line and check for its monotonicity -1