Question number 16. Please give a shortcut method (if any). Q16. The continued product of (1 + x) , (1 + x2) , (1 + x4), (1 + x8 ) and ( 1 – x ) is : (A) ( 1 – x16 ) (B) ( x16 – 1) (C) ( 1 – x8 + x16) (D) ( x8 + x16 ) Share with your friends Share 1 Sanjari Kalantri answered this Dear Student, We use the identity a2 - b2 = (a + b)(a - b) repeatedly to solve the given question.(1 - x)(1 + x)(1 + x2)(1 + x4)(1 + x8) = (1 - x2)(1 + x2)(1 + x4)(1 + x8) = (1 - x4)(1 + x4)(1 + x8) = (1 - x8)(1 + x8) = (1 - x16) 0 View Full Answer