Question 7 7 . T h e v a l u e o f log 3 24 + 24 + 24 + . . . . . . . . . . ∞ 3 3 3 ( A ) 1 ( B ) log 3 24 ( C ) 2 ( D ) 1 3 1 + 3 log 3 2 Share with your friends Share 0 Aarushi Mishra answered this Let y=24+24+24+24+...∞3333y=24+y3y3=24+yy3-y-24=024=3×2×2×2Using hit and trial find root of cubic equationPut y=333-3-24=27-3-24=0Hence y=3 is a root of the cubic equationSo y-3 is its factor y3-y-24=y-3y2+3y+8=0Note: discriminant of the quadratic y2+3y+8, D=9-32<0So it has imaginary rootsHence y=3 is the only solutionNowlog324+24+24+24+...∞3333=log3y=log33=1 -1 View Full Answer Bharat Chandra answered this is this fiitjee or vmc material? 1