Q Let S = (1, 2, 3,...9). For k = 1, 2,...5, let N k be the number of subsets of S, each containing five elements 
out of which exactly k are odd.  Then   N 1 + N 2 + N 3 + N 4 + N 5
A) 125 
B) 252 
C) 210 
D) 126 

Q. ​Q Let   S = x R : x 0   a n d   2 x - 3 + x x - 6 + 6 = 0 .   . Then S 
A) contains exactly two elements 
8) contains exactly four elements. 
C) is an empty set 
D) contains exactly one element. 

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