Q.9. The activity of the radioactive sample drops to 1 64 t h of its original value in 2 hr find the decay constant λ . Share with your friends Share 2 Shyama Charan Mandal answered this Dear Student, Find your answer below:-- AAo=(12)tT1/2=>164=(12)t/2=>(12)6 =(12)t/2=>t2=6=>t=12 hr Regards, -8 View Full Answer