PREMA RECEIVED A CERTAIN AMOUNT OF MONEY ON HER RETIREMENT FROM HER EMPLOYER.SHE GIVES HALF OF THE MONEY AND AN ADDITIONAL SUM OF RS.10000 TO HER DAUGHTER.SHE ALSO GIVES ONE-THIRD OF THE MONEY RECEIVED AND AN ADDITIONAL SUM OF RS.3000 TO HER SON.IF THE DAUGHTER GETS TWICE AS MUCH AS THE SON,FIND THE AMOUNT OF MONEY RECEIVED ON HER RETIREMENT.

EXPLAIN THESE AND GIVE A DETAILED SOLUTION.

DONT GIVE LINKS,PLZ.



Dear Student,

Let the amount received by Hema be 'x'. Then her daughter got (x/2 + 10000) and Hema's son was given (x/3 + 3000).

and given that


2x3+3000 = x2+10000          (1)

or 2x3-x2 = 10000 - 60004x6-3x6=4000x = 6×4000 = 24000


The amount received by Prema is 24000.  The solution can be verified by substituting for x = 24000 in equation (1).



Regards

  • 0
x/2+10000=2(x/3+3000)
x+20000  =2x/3+6000
     2
                =2x+18000
                       3
2(2x+18000)=3(x+20000)
4x+36000=3x+60000
4x-3x=60000-36000
x=24000
Prema recives Rs 24000
  • -1
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