Please solve this question.... Share with your friends Share 0 Atul Shaw answered this Solution:OA=OBSo, ∠OAB=∠OBAIn tri. AOB,∠AOB+∠OBA+∠OAB=180°90°+∠OAB+∠OAB=180°2∠OAB=90°∠OAB=45°next, 2∠ACB=∠OAB(The angle subtended by an arc of a circle at its center is twice the angle it subtends anywhere on the circle's circumference.)∠ACB=∠OAB2=45°in tri. CAB,∠CAB+∠ACB+∠ABC=180° (Sum of angles of a triangle)45°+30°+∠CAB=180°∠CAB=105°Now, ∠CAB=∠CAO+∠OAB (from fig.)105°=∠CAO+45°∠CAO=60°Option D 1 View Full Answer
