please solve the following question:- A reaction SO2Cl2 ---->SO2 + Cl2 is a first order reaction with half life time period 3.5*104s at 320C . What percentage of SO2Cl2 would be decomposed on heating at 320 C FOR 90 mins.
Solution-
Total time T = n x t1/2
t1/2 = 3.5 x 104 sec =35000 seconds
T = 90 minutes = 5400 seconds
Let the initial amount is N° and the final amount of reactant is N
------(1)
K = 0.693/ t1/2 ------(2)
Therefore from equation (2)
K = 1.98 x 10-5
Putting the value of k and t in equation (1)
log No/N = 0.0000198 5400 = 0.1069
Taking antilog on both sides,
N°/N = antilog 0.1069
N°/N = 1.279
Therefore remaining amount (N) = 0.7818 N°
% Amount decomposed = (N° - 0.7818 N°) x 100/N°
= 21.81%