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Dear Student
   Power of the bulb = 60 watt
        $$\begin{gathered} Energy of proton, \\ E =n h\frac{c}{\lambda } \\ h = 6.626\times {10}^{-34}Js \\ c = 3\times {10}^{8}m/s \\ \lambda = 600\times {10}^{-9}m \\ Therefore, E=n \frac{6.626\times {10}^{-34}Js\times 3\times {10}^{8}m/s}{600\times {10}^{-9}m} \\ E = Pt \\ n \frac{6.626\times {10}^{-34}Js\times 3\times {10}^{8}m/s}{600\times {10}^{-9}m} = 60 \times 1 \\ n = \frac{600\times {10}^{-9}m\times 60 J/s}{6.626\times {10}^{-34}Js\times 3\times {10}^{8}m/s}= \mathbf{2}\mathbf{.}\mathbf{012}\mathbf{\times }{\mathbf{10}}^{\mathbf{20}}\mathbf{ }\mathit{P}\mathit{h}\mathit{o}\mathit{t}\mathit{o}\mathit{n}\mathit{s} \end{gathered}$$

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