Please help me with 20th sum
correct answer is 10

Dear Student,
Please find below the solution to the asked query:

xy=c c>0        .....ix2+y2=25         .....iiFrom i and ii, we getcy2+y2=25c2y2+y2=25c2+y4=25y2y4+25y2+c2=0     .....iThis means, y can have maximum of four values i.e. the number of point of intersection can be maximum 4.But it is given that the point of intesection is two.The equation must have two equal roots.So, D=0252-4×1×c2=0625-4c2=0c2=6254c=252     c>0So, using i, we gety4+25y2+6254=0           y22+2×y2×252+2522=0y2+2522=0y2=252y=±52If y=-52,thenx=cy=252-52x=-52If y=52,thenx=cy=25252x=52So, the two point of intersection are A-52,-52 and B52,52.Now, the distance AB=52+522+52+522=1022+1022=21022=21022=102 AB=10 units

Hope this information will clear your doubts about the topic.
Regards

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