Please don't give links and give proper reasons of each step in your solution with your suitable figure ( the correct option of given question is b)

Dear studentLet θ is the angle made by the stone at that instant so,mv2L=mg-mgcosθv2=Lg(1-cosθ)......................................(1)usng law of ceonservation of energy we have,12mgL=12mv+mgL(1-cosθ)v2v2=gL-2gL(1-cosθ)......................................(2)solving eqn 1 and 2 we getgL-2gL(1-cosθ)=Lg(1-cosθ)θ=cos-123so, v2=10×151-23=5v=507m/sRegards

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