# please answer it fast

$Weknowthat,\phantom{\rule{0ex}{0ex}}Areaofrt\u2206=\frac{1}{2}\times base\times height\phantom{\rule{0ex}{0ex}}thenAreaofrt\u2206ABC=\frac{1}{2}\times BC\times AD\phantom{\rule{0ex}{0ex}}=\frac{1}{2}\times 5.5\times 4\phantom{\rule{0ex}{0ex}}=5.5\times 2\phantom{\rule{0ex}{0ex}}=11c{m}^{2}$

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