PLEASE ANSWER CORRECTLYPLEASE ANSWER CORRECTLY O taff O 2. loge loge o 4. tan- is equal to: 2X+1 Share with your friends Share 1 Neha Sethi answered this Dear student ∫dx2x+11+2x+1Put u=2x+1 ⇒dx=du2=12∫1u+1uduNow expanding fraction by 1u32=12∫11u+1u32duPut v=1u+1 ⇒du=-2u32dv=-∫1vdv=-logv+C=-log1u+1+C=-log12x+1+1+C=-log1+2x+12x+1+C Regards 0 View Full Answer