one mole of a gas with gamma=5/3 is initially at temperature 27 C and occupy volume V.The gas is first expanded at constant pressure until its volume double.Then it undergoes an adiabatic change until the temperature returns to its initial value.Find the work done

Dear student
since when volume is doubled keeping temp constant the temperature also gets double hence T1=300K and T2=600K
Total work done =Wconstant pressure+Wadiabatic  = nRx300 + nR(T1- T2)/(5/3 -1)
W =300R-450R=-150R=  -150 x 8.314 =  -1247.1 J


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