in triangle PQR, PS is perpendicular to QR and PS2 = QS* RS, then prove that PQR is right angles at P


PS2=QS.RSPSQS=RSPSIn PSR and QSPPSQS=RSPSPSR=QSP=90°By SAS Similarity criterion ,PSR~QSPTherefore, RPQ=90°By converese of theorem , that perpendicular drawn from right angled of right angled triangles divides the triangle in two similar triangles.

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