in triangle PQR, PS is perpendicular to QR and PS2 = QS* RS, then prove that PQR is right angles at P Share with your friends Share 3 Rishabh Mittal answered this PS2=QS.RSPSQS=RSPSIn △PSR and △QSPPSQS=RSPS∠PSR=∠QSP=90°By SAS Similarity criterion ,△PSR~△QSPTherefore, ∠RPQ=90°By converese of theorem , that perpendicular drawn from right angled of right angled triangles divides the triangle in two similar triangles. 7 View Full Answer