If N is the smallest natural number such that N+2N+3N+....+99N is a perfect square then thenumber of digits in N^2 is Share with your friends Share 2 Neha Sethi answered this Dear student Sum =99×50×n=32×52×22×n= perfect square⇒nmin=22⇒n2=484⇒ Number of digits =3 Regards 0 View Full Answer
