If a and b are
Dear student,
given ,
(|a + b|)2 = |a|2 [ squaring on both sides
( a + b ) · ( a + b ) = a · a
a · a + b · a + a · b + b · b = a · a
2 a · b + b · b = 0 [ sin c e b · a = a · b
( 2 a + b ) · b = 0
since the dot product is zero, so angle should be 90 degrees between these two vectors.
thus, vector (2a+b) is perpendicular to vector b.
Regards
given ,
(|a + b|)2 = |a|2 [ squaring on both sides
since the dot product is zero, so angle should be 90 degrees between these two vectors.
thus, vector (2a+b) is perpendicular to vector b.
Regards