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how to find the oxidation number of H2S2O8

this will help u out...read it..

2 +2x -16=0

=>x =7  ,,but for sulphur x cannot be greater than 6... so this means , there is a peroxy linkage in the given compound...

and we know that ,  peroxy oxygen have oxdn. no. -1

whenever there is peroxy linkage , sulphur is always in its highest oxdn. state i.e. +6

so here, oxdn. state of sulphur is +6

now u can also find the no. of peroxy linkages..

i.e.  2+2(6) +n(-1) -(n-8)(-2) = 0

so , here n = 2.  so we have two peroxy oxygens and one peroxy linkage.....

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  • -19
2H+2S+8O=0
2+2S+(-16)=0
2+2S=16
2S=16-2
2S=14
S=7
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H=1
O=-2
S=x
H2S2O8
2(1)+2(x)+8(-2)=0
2+2x-16=0
2x=14
x=7
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Peroxydisulfuric acid is a sulfur oxoacid with the chemical formula H2S2O8. It is also called Marshall's acid. In structural terms it can be written HO3SOOSO3H. It contains sulfur in its +6 oxidation state, but it also contains a peroxide group, which is why it appears to be in a higher oxidation state than sulfates. Its salts, commonly known as persulfates, are industrially important but the acid itself is not. The salts contain the peroxydisulfate ion. They are powerful oxidizing agents.
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Please find this answer

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ON of H is +2, O is-16 so you can easily find the oxidation number.
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Sorry

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Please find this answer

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Take sulphur oxidation no. =x
Take H ox. no.=+1
Take O ox. no.=-2

(1)2+(x)2+(-2)8=0
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