How can we construct a parallelogram ABCD in which AB = 6.5 cm , AC = 3.4 cm and the altitude AL from A is 2.5 cm .

Please explain the steps of construction.

Hi!

Here is the answer to your question.

**Follow the given steps to construct the parallelogram ABCD.**

Step 1. Draw AB = 6.5 cm.

Step 2. At A, draw AE ⊥ AB. With A as centre and radius 2.5 cm, mark an arc which intersects AE in F.

Step 3. Draw a line parallel to AB and passing through F.

Step 4. With A as centre and radius 3.4 cm, mark an arc which intersects the line parallel to AB in C.

Step 5. With C as centre and radius 6.5 cm, mark an arc which intersects the line CF in D.

**(Opposite sides of parallelogram are equal)**Step 6. Join BC and DA.

Thus, ABCD is the required parallelogram.

Best Wishes!

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