find the least 5-digit number which on dividing by 4,12,20 and 24 leaves remainder 3 in each case
We have to find a 5 digit number which on dividing by 4,12,20 and 24 leaves remainder 3 in each case.
So,
LCM(4,12,20,24) = 120
So to obtain a five digit number we have to multiply the LCM by 84.
Therefore the required number
= 10080 + 3
= 10083