Find req about AB... Also pls tell which symm aur law u are using

Look at the symmetry of the circuit. The battery (suppose) is connected between points A and B.
From the symmetry current in AO will be same as current in OB
Similarly current CO equal to current in OD
The given circuit can be redrawn as

R =4+4+114+18 =8 +12+18 =8 +83 =3231RAB =14 +18 +1323 =14 +18 +332 =8+4+332=1532RAB =3215 Ohm

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