experts pls reply fastt with solution of all these problems
Solution:
(1).
Given, p(x)=4x³-7x²+4x+7
(1).
Given, p(x)=4x³-7x²+4x+7
Put x=2, we get
p(2)=4(2)³-7(2)²+4(2)+7
p(2)=4(8)−7(4)+8+7
p(2)=32−28+8+7
p(2)=47−28
p(2)=19
(2).
Let P(x)=4x³-7x²-2x+5
Putting x=1,we get
(2).
Let P(x)=4x³-7x²-2x+5
Putting x=1,we get
P(1)=4(1)³-7(1)²-2(1)+5
P(1)=4-7-2+5
P(1)=0
So, 1 is the zero of P(x).
For remaining queries,we request you to post them in another thread to have a rapid assistant from our experts.
P(1)=4-7-2+5
P(1)=0
So, 1 is the zero of P(x).
For remaining queries,we request you to post them in another thread to have a rapid assistant from our experts.