Eight children are standing in a queue i) in how many ways can the queue be formed ii)how - Maths - Permutations and Combinations

Question

Eight children are standing in a queue
i) in how many ways can the queue be formed?
ii)how many arrangements are possible if the tallest child stands
at the end of the queue?

Rishabh Mittal · Accepted Answer

Dear Student ,

Please find below the solution to the asked query :

1 Number of ways in which queue can be formed=8!=8×7×6×5×4×3×2×1=40320 ways 
2 Number of arrangements , if tallest child stands at the end of queue=7!=7×6×5×4×3×2×1=5040 ways 
Hope this information will clear your doubts about the topic
If you have any more doubts just ask here on the forum and our
experts will try to help you out as soon as possible

Regards

Eight children are standing in a queue. i) in how many ways can the queue be formed? ii)how many arrangements are possible if the tallest child stands at the end of the queue?

Eight children are standing in a queue.
i) in how many ways can the queue be formed?
ii)how many arrangements are possible if the tallest child stands at the end of the queue?