cot^2A.cot^2B=3 , find the value of (2-cos2A)(2-cos2B)

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Please find below the solution to the asked query:

We havecot2A cot2B=3Take cotA=3 and cotB=1 which will satisfy above equationA=π6 and B=π42-cos2A2-cos2B=2-cosπ32-cosπ2=2-122-0=32×2=3 Answer

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