complete the following:-a)CH3-CH=CH2+HBr in the presence of peroxide gives?
b)CH3CH-Br-CH2-CH3+KOH(alc) gives?

Dear student,

Please find below the solution to the query posted by you.

Reaction a):
${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2 + \mathrm{HBr} \stackrel{ \mathrm{Peroxide} }{\to } \underset{\mathrm{Major}}{{\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2\mathrm{Br}}$
Reaction b): 
${\mathrm{CH}}_3-\mathrm{CH}\left(\mathrm{Br}\right)-{\mathrm{CH}}_2-{\mathrm{CH}}_3 \stackrel{ \mathrm{Alc}. \mathrm{KOH} }{\to } {\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-{\mathrm{CH}}_3$

Hope this information will clear your doubt regarding reaction of alkyl halides.

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