# common salt obtained from sea water contains 96% NaCl by mass. the approx. no. of molecules present in 10 g of the salt is a.1021b. 1022c. 1023d. 1024

Sea water contains 96% of NaCl by mass

Therefore, 100g of water will have 96g of NaCl

10g of water will have 9.6g of NaCl

Moles of NaCl in 9.6g of NaCl: (Molar mass of NaCl = 58.5g)

9.6 / 58.5 = 0.164 moles

Number of molecules in 9.6g, 0.164 moles = 0.164 * 6.023 * 10^23

= 9.87 * 10^22 molecules

= 10^23 molecules

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Mass of NaCl in 100g sea water common salt = 96g

= Mass of NaCl in 10g sea water common salt = 9.6g

Molecular mass of NaCl = 58.5gm

Moles of NaCl = 9.6/58.5 = 0.164 moles approx

Therefore, molecules present in 9.6 gms of NaCl = 0.164*6.022*1023 = 0.987*1023 molecules.

So, from the above options, the correct one will be C. 1023 molecules

Hope this helps!

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* C. 1023

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It seems that the superscript function of this website isn't working properly. In actual, the no. of molecules will be 10^23 molecules.

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