Can we construct triangle PQR if angle Q is 30 degree and R is60 degree and QR is 4.7 cm ? 

Dear Student,

Please find below the solution to the asked query:

We follow these steps :

Step : Draw a line QR  = 4.7 cm

Step 2 : Take any radius ( Less than half of line QR ) and center " R " draw an arc that intersect our line QR at " A " . With same radius and center " A " draw another arc that arc intersect our previous arc at " B " .

Step 3 : Join RB and extend to " S "  we get line RS .

Step 4 : Take any radius ( Less than half of line QR ) and center " Q " draw an arc that intersect our line QR at " C " . With same radius and center " C " draw another arc that arc intersect our previous arc at " D " . Now with same radius and center " C " and " D " draw two arcs these arcs intersect at " T " .

Step 5 : Join QT and extend so that line intersect our line RS at " P " .



Hope this information will clear your doubts about Construction.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards

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