Calculate the equilibrium constant of the reaction at 298 K . Mg(s) + 2Ag+(aq) --> Mg2+(aq) +2Ag(s); E0 cell=+3.16 V Share with your friends Share 3 Vartika Jain answered this Dear Student, ∆G°=-nFE°celland, ∆G°=-RTlnKeqTherefore, nFE°cell=RTlnKeqor, lnKeq=nFE°cellRTHere, n=2 (as 2 electrons are involved)F=96500 E°cell=3.16 VR=8.314 JK-1mol-1T=298 Kor, lnKeq=2×96500×3.168.314×298=246.16or, Keq= e246.16=8.05 2 View Full Answer