by what least number should 27648 be divided so that the quotient becomes a perfect cube - Maths - Cubes and Cube Roots

Question

by what least number should 27648 be divided so that the
quotient becomes a perfect cube?

Ajanta Trivedi · Accepted Answer

the given number is 27648 the factors of the number is given as: $27648 = 2^{10} \times 3^{3} = 2^{3} \times 2^{3} \times 2^{3} \times 2 \times 3^{3}$ now other than 2 ,all the factors are in the pair of 3 so if we will divide the number 27648 by 2, it will make the perfect cube of $2 \times 2 \times 2 \times 3 = 24$ hope this helps you cheers!!

by what least number should 27648 be divided so that the quotient becomes a perfect cube?