Ans both question

Dear student
Q106)Let the numbers be x,y,z,u,v
So we have
$$\begin{gathered} \frac{x+y+z+u+v}{5}=10 \\ Hence \\ \frac{(x-3)+(y-3)+(z-3)+(u-3)+(v-3)}{5}=\frac{{\displaystyle x+y+z+u+v}}{{\displaystyle 5}}-3=10-3=7 \end{gathered}$$
Q107)
We have
​​​​​$$\begin{gathered} Let h be the height so we have \\ r=\frac{5h}{3} \\ Hence CSA=2\pi rh=2\times \pi \times \frac{5h}{3}\times h=\frac{10\pi h^2}{3} \\ Hence we have \cos t =Rs\frac{10\pi h^2}{3}\times \frac{2}{100}=\frac{\pi h^2}{15} \\ So we have \\ \frac{\pi h^2}{15}=92.40 \\ h=21 \\ So that we have r=35 \\ V=\pi r^{2}h=80817.47c{m}^2 \\ Regards \end{gathered}$$