an electron accelerated by a potential difference of 300V ,is moving at a distance of 4mm from a long staight wire.If current of 5A flows through the wire,what will be the force acting on the electron? ans is 4*10^-16N V Share with your friends Share 38 Vara answered this Speed of the electron:Work done=Kinetic energyqV=12mv2v=2qVm =21.6×10-193009.1×10-31 =1.03×107 m/sMagnetic field due to current carrying wire:B=μo2πir =4π×10-72π54×10-3 =0.00025 TForce on the electron:=Bqv=0.00025×1.6×10-19×1.03×107=4×10-16 N 49 View Full Answer