An angular impulse of 20 Nms is applied to a hollow cylinder of mass 2 kg and radius 20 cm. The change in its angular speed is? Share with your friends Share 35 Dinesh Pandey answered this Dear Student, angular impulse, L=20 NmsMass, m=2 kgradius, r=20 cm=0.2 mL=Iωf-ωiwhere, I=moment of inertia=mr2ωf-ωi=change in angular speedL=mr2ωf-ωi20=2×0.22×ωf-ωiωf-ωi=202×0.04ωf-ωi=250 rad/s 225 View Full Answer