# A diatomic molecule has a dipole moment of 1.2D if the bond length is 1.0 x 10^-8 cm, what fraction of charge does exist on each atom?

Please find below the solution to the asked query:

Dipole moment is calculated by the following formula:

$\mu =q\times \times l\phantom{\rule{0ex}{0ex}}where\phantom{\rule{0ex}{0ex}}\mu isdipolemoment=1.2D=1.2\times 3.336\times {10}^{-30}Cm\phantom{\rule{0ex}{0ex}}qismagnitudeofcharge\phantom{\rule{0ex}{0ex}}lisdis\mathrm{tan}cebetweenchargesorbondlength=1\times {10}^{-8}cmor1\times {10}^{-10}m\phantom{\rule{0ex}{0ex}}$

_{$q=\frac{1.2\times 3.336\times {10}^{-30}}{1\times {10}^{-10}}\phantom{\rule{0ex}{0ex}}q=4\times {10}^{-20}C\phantom{\rule{0ex}{0ex}}\text{fractionofcharge}=\frac{4\times {10}^{-20}}{1.6\times {10}^{-19}}=0.25\phantom{\rule{0ex}{0ex}}$}

Hope this information will clear your doubts about determining the fraction of charge on a diatomic atom with a dipole moment.

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