A chord of circle of radius 10 cm subtends a right angle at the centre.Find the area of the corresponding minor segment and hence find the area of the major sector?

Let r be the radius of the circle and θ be the angle subtended by the chord at the centre.

Given, r = 10 cm and θ = 90°

Area of the minor segment

= Area of sector OAPB – Area of ∆AOB

Area of the major sector OAQB

= Area of circle – Area of sector OAPB

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