A and B can separately complete a piece of work in 20 days and 30 days respectively,they worked together for some time.then B left the work.if A  completed rest of the work in 10 days then B worked for how many days?please give meaningful step by step answer,not any similar link.  

Number of days taken by A to complete the work alone = 20 daysNow, A's 1 day's work = 120Number of days taken by B to complete the work alone = 30 daysNow, B's 1 day's work = 130Now, A+B's 1 day's work = 120 + 130 = 3+260 = 112Suppose thew worked together for x days.Now, A+B's x days' work = x12Now, amount of work left = 1 - x12 = 12-x12Now, number of days taken by A to complete rest work = 20 × 12-x12 = 5312-xAccording to question :    5312-x = 1012 - x = 6x = 6So, B worked for 6 days.

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