6 .   A   c l o s e d   c y l i n d r i c a l   w a t e r   tan k   i s   m a d e   f r o m   a   p l a s t i c   s h e e t .   I t s   d i a m e t e r   i s   1 . 4 m   a n d   h e i g h t   3 . 5 m .   F i n d     ( i )   L a t e r a l   ( c u r v e d )   s u r f a c e   a r e a   o f   t h e   tan k .     ( i i )   a c t u a l   a r e a   o f   t h e   p l a s t i c   s h e e t   u s e d   i f   1 13     o f   s h e e t   a c t u a l l y   u s e d   w a s   w a s t e d   i n   m a k i n g   tan k .   ( T a k e     π = 3 . 14   ) 10 .   A   l o n g   a   h i g h w a y   50 c o n i c a l   p i l l a r s   a r e   c o n s t r u c t e d .   E a c h   P i l l a r   h a s   b a s e   d i a m e t e r   28   c m   a n d   v e r t i c a l   h e i g h t     18 c m .   f i n d   t h e   t o t a l   cos t   o f   p a n t i n g   t h e s e   p i l l a r s   a t   t h e   r a t e   o f   R s .   120   p e r   m 2 . ( T a k e   π =   22 7   )  

Dear Student,

The solution to your ( 10th) query has been provided below:

Given : 50 conical pillars with base diameter =  28 cm  and vertical height = 18 cm

So,

Radius of a conical pillar = r = 14 cm and Height of a conical pillar = h = 18 cm
 
We know curved surface area of cone = π r r2 + h2 , So

Curved surface area of a conical pillar = 227 × 14× 142 + 182 = 22 × 2× 196 + 324= 22 × 2× 520 =  22 × 2×22.8035 = 1003.354 cm2

So,

Curved surface area of 50 conical pillar =  50 × 1003.354 = 50167.7 cm2  = ( 50167.7 × 0.0001 ) m2 = 5.01677m2       ( We know 1 cm2 = 0.0001 m2

Also given : Rate of painting =  120 per m2 ,

Therefore,

Cost of painting these pillars  =  120 × 5.01677 = 602.0124 Rs. 602                                                  ( Ans )

Hope this information will clear your doubts about topic.

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